C++ program to find the reverse of a number.

#include<iostream.h>

#include<conio.h>

void main()

{clrscr();

intr,n,rev=0;

cout<<"enter any no.=";

cin>>n;

do

 {r=n%10;

rev=10*rev+r;

 n=n/10;

 }

while(n!=0);

cout<<"reverse no. is="<<rev;

getch();

 }

OUTPUT

enter any no.=54

reverse no. is=45